In the figure area of bc=4cm cd=4cm de=8cm find the ratio of the areas of triangle abc, acd, ade
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Step-by-step explanation:
Given: DE || BC DE = 4cm, BC = 8cm and area (ΔADE) =25 sq. cm In ΔABC and ΔADE ∠B = ∠D [∵ DE || BC and AB is transversal, Corresponding angles are equal] ∠C = ∠E [∵ DE || BC and AC is transversal, Corresponding angles are equal] ∠BAC =∠DAE [common angle] ∴ ΔABC ~ΔADE [by AAA similarity] Now, we know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.
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