Question

in the figure, area of parallelogram LMNO is 240 sq.cm . Find the area of: i) parallelogram PMNQ, ii) triangle PMQ​

Answer 1

The area of

i) parallelogram PMNQ = 240 $cm^{2}$

ii) triangle PMQ​ = 120 $cm^{2}$

Step-by-step explanation:

The figure is attached below:

As we know that

1. The area of parallelogram is

= ${base\times{height}$

That is 240 $cm^{2}$ of LMNO parallelogram

Now the area of parallelogram PMNQ is also 240 $cm^{2}$ due to the same base and the height. The base is PM and the height is the perpendicular distance between parallels lines i.e MN and LQ

2. Moreover, the area of the triangle is

=  $\frac{1}{2}\times{base\times{height}$

So, it also equal to the area of parallelogram PMNQ due to the same base and the height. The base is PQ and the height is the perpendicular distance between parallels lines i.e PM and NQ

So, the area of triangle of PMQ is

= $\frac{1}{2}\times 240cm^{2}$

=  120 $cm^{2}$

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In the figure,area of parallelogram LMNO is 240cm^.Find the area of:1.parallelogram PMNQ

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