In the figure area of triangle ABD is 10sq.cm and area of triangle
ADC is 12 sq.cm
a) Find BD:DC
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Answer:
Area ∆adb=h×b1 of 2
10 =hx 5/2
h=4 cm
Aren of ∆adc = hxb2/2
12 = 4cm×b2 of 2
cd/b2 = 24/4 = 6cm And bd:dc Ans
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