In the figure, as if AB parallel to CF & CD parallel to FE, then find the value of x
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acc. to angle sum property in ∆ABC,
45+65+BAC=180
BAC=180-105=75°
as AB is parallel to CF, thus angle BAC = angle FCD(corresponding angle )
thus,angle FCD=75
now as FE is parallel to CD
angle EFC+FCD=180
(co.int.angles)
X=180-75
X=105°
hope it helps u..
45+65+BAC=180
BAC=180-105=75°
as AB is parallel to CF, thus angle BAC = angle FCD(corresponding angle )
thus,angle FCD=75
now as FE is parallel to CD
angle EFC+FCD=180
(co.int.angles)
X=180-75
X=105°
hope it helps u..
Answered by
22
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