Question

In the figure AX parallel BY, O is the midpoint of AB, < X= 60 then find (a) < Y
(b) < AOX
(c) < BOY​

Answer 1

Answer:

In ∆AOX and ∆BOY

<A = <B (AX is parallel to BY)

<AOX = <BOY (V.O.A)

AX = BY ( O is the mid point of AB)

∆AOX ≈ ∆BOY (ASA congruency)

<X = <Y (c.p.c.t)

<Y = 60°

<AOX = <BOY (c.p.c.t)