Question

in the figure axb is a semicircle and ab is the diameter ab= 12 cm arc ayb is an arc having measure 120 degree find area of shaded region

Answer 1

Answer:

ab=12cm

axb=?

therefore

m of semicircle=180

180÷12=15

15 area of shaded portion

Answer 2

Area of shaded region is 63.48 cm².

To find : Area of shaded region.

Given :

AXB is a semicircle.                                                        

AB is a diameter.                                                                        

AB = 12 cm.                              

Arc AYB = 120°                              

To find area of semi-circle :

Area of semi-c ircle = $\frac{\pi\times r^2 }{2}$      

Radius ( r ) = $\frac{Diameter}{2}$ = $\frac{12}{2}$ = 6 cm.

r = 6 cm.

Area of semi-circle = $\frac{\pi\times (6)^2}{2}$ = $\frac{\pi\times 6\times\ 6}{2}$

                               = $\frac{3.14 \times 6 \times 6 }{2}$              [ π = 3.14 ]

                               = $\frac{113.04}{2}$

Area of semi-circle = 56.52 cm².

To find area of shaded region :

Area of shaded region = Arc AYB - Area of semi-circle

                                      = 120° - 56.52

                                      = 63.48 cm²

Therefore, area of shaded region is 63.48 cm².

To learn more...

1. Find the area of the segment AYB shown in fig., if radius of the circle is 21cm and angle AOB = 120 degree. ( use pie = 22/7 )

brainly.in/question/2784725

2. A metallic sphere of radius 21 cm is dropped into a cylindrical vessel, which is partly filled with water. The diameter of the vessel is 1.68m. If the sphere is completely submerged, find by how much the surface of water will rise?

brainly.in/question/7279494