In the figure B= 90 degrees, AD=15 and DC=20. If BD is the bisector of angle ABC, what is the perimeter of the triangle ABC?
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Answer:
Given AB=18 cm, AC=15 cm and BC=22 cm
By angle bisector theorem, if bisector of ∠A meets side BC at D, then
AC
AB
=
DC
BD
AC
AB
=
BC−BD
BD
Substituting values of AB,AC and BC
15
18
=
22−BD
BD
5
6
=
22−BD
BD
(22∗6)−6BD=5BD
∴BD=12cm.
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