Question

In the figure,∟B=90˚ . So∟ A+∟C=90˚ . That is, if ∟A= x, then ∟C = 90-x



tanA= BC

AB , tanC = AB

BC and A

tanA ×tanC = BC

AB ×

AB

BC = 1

As the angle measure increases from zero to 90˚ ,tan value is also

increasing from zero.

Now fill in the blanks:

a) tan 0 = ...........

b)If tanA ×tanC =1, then A+C = ......... B C

c) tan1 ×tan89 = ...........

d) tan45 = ...........

e) If tanx = tan(90-x), then x = .............

f) tan1 ×tan 2 × tan3 ×.........×tan89 = .........​

Answer 1

Answer:

We have,

cos49 ∘

sin41 ∘

= cos49 ∘

sin(90 ∘−49 ∘ )

= cos49 ∘

cos49 ∘

=1 [∵sin(90∘ −θ)=cosθ]