In the figure∠BAC= 55°, then find∠AED
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I think answer is the 135
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Given:
∠B = 55°
AD is perpendicular to BC.
AE is the angle bisector of ∠DAB.
Concept:
The sum of all angles of a triangle is 180.
The angle bisector is a line that divides the angle into two equal parts.
Calculation:
F1 Amar Kumar Anil 19-05.21 D12
In ΔABD,
∠ABD + ∠BAD + ∠ADB = 180°
⇒ 55° + ∠BAD + 90° = 180
⇒ ∠BAD = 180 - 145
⇒ ∠BAD = 35°
According to the question,
∠EAD = ∠BAD/2
⇒ ∠EAD = 35/2
⇒ ∠EAD = 17.5°
Now, In ΔADE we can write,
∠ADE + ∠AED + ∠EAD = 180
⇒ 90° + 17.5° + ∠AED = 180
⇒ ∠AED = 180° - 107.5°
⇒ ∠AED = 72.5°
∴ The measure of ∠AED is 72.5°.
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