Math, asked by rrinu363, 1 month ago

In the figure, BC = 12cm, BD = 3cm. Area of △ABC is 80cm². a) What is BD : DC? b) Find the area of △ADC.​

Answers

Answered by sahvish
3

Answer:

Answer: The area of Δ ADC= 60 square cm.

Explanation:

Since we have given that

BC=12

BD=3

DC=BC-BD=12-3=9

So, BD:DC=3:9=1:3

So, we can let

BD=x and DC=3x

Now,

∆ABD. 1/2×x×h. 1

---------- = ----------- = ---

∆ADC. 1/2×3x×h 2

So,

3ABD=ADC

Now

∆ABD+∆ADC=∆ABC

∆ADC

---------=∆ADC=∆ABC

3

4∆ADC

----------- =80

3

ΔADC=60 square cm

Step-by-step explanation:

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