In the figure, BC = 12cm, BD = 3cm. Area of △ABC is 80cm². a) What is BD : DC? b) Find the area of △ADC.
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Answer:
Answer: The area of Δ ADC= 60 square cm.
Explanation:
Since we have given that
BC=12
BD=3
DC=BC-BD=12-3=9
So, BD:DC=3:9=1:3
So, we can let
BD=x and DC=3x
Now,
∆ABD. 1/2×x×h. 1
---------- = ----------- = ---
∆ADC. 1/2×3x×h 2
So,
3ABD=ADC
Now
∆ABD+∆ADC=∆ABC
∆ADC
---------=∆ADC=∆ABC
3
4∆ADC
----------- =80
3
ΔADC=60 square cm
Step-by-step explanation:
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