Math, asked by faisal3897, 1 year ago

in the figure BC =12cm,BD=3cm area of the triangle ABC is 80sq.cm what is BD: DC
find the area of the triangle ADC

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Answers

Answered by RenatoMattice
74

Answer: The area of Δ ADC= 60 square cm.

Explanation:

Since we have given that

BC=12

BD=3

DC=BC-BD=12-3=9

So, BD:DC=3:9=1:3

So, we can let

BD=x and DC=3x

Now,

\frac{\Delta ABD}{\Delta ADC}=\frac{\frac{1}{2}\times x\times h}{\frac{1}{2}\times 3x\times h}=\frac{1}{3}

So,

3ABD=ADC\\

Now,

\Delta ABD+\Delta ADC=\Delta ABC\\\\\frac{\Delta ADC}{3}+\Delta ADC=\Delta ABC\\\\\frac{4\Delta ADC}{3}=80\\\\\Delta ADC=60\text{ square cm}


Answered by REMYA57616
6

Answer:

60cmsq

Step-by-step explanation:

area of triagnle ABC = 80 cmsq     then the area of triangle adc = 80-20 = 60 so the triangle abd = 20

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