Question

in the figure, BC=14cm AC=15cm AB=13cm AD=12cm OB-BQ OA-AP angle D=90.... find the length of PQ​

Answer 1

Answer:

see the refference

and solve

Step-by-step explanation:

Area of the rectangle ABCD=12×7=84sqcm.

Let AP=x cm. So, PB=(12−x) cm.

Area of shaded region =0.4×84=33.6 sq cm.

Area of triangle EAP=0.5×5×x=2.5x sq cm

Area of triangle CPB=0.5×7×(12−x)=42−3.5x sq cm

Sum of the area of triangles EAP and CPB = area of shaded region

2.5x+42−3.5x=33.6

42−x=33.6 or x=8.4cm