Question

In the figure,BC = 7, BD = 3 ,Then write the ratio A(∆ ABD) / A (∆ABC)
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Answer 1

Answer:

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Step-by-step explanation:

Draw AP ⊥ BD

i.e., AP is the height of Δ ABD as well as Δ ABC

We know,

Area of triangle= 1/2 × base × height

Therefore,

Area of Δ ABD = 1/2×AP×BD=1/2×AP×3

and

Area of Δ ABC = 1/2×AP×BC=1/2×AP×7

Now,

The ratio of A(∆ABD) and A(∆ABC) is,

= 1/2×AP×3 ÷ 1/2×AP×7

= 3/7

Thus, the ratio of the areas of the triangles are:

AREA(Δ ABD) ÷ AREA(Δ ABC) = 3/7