Question

in the figure BC=AC,B=70° FIND A and C​

Answer 1

$\huge\bold{Answer}$

B=A=70°(As equal sides subtain equal angles at the centre)

Now,

A + B + C = 180° (Angle sum property)

70° + 70° + C =180°

C= 40°

Thus,

$\huge\boxed{A=70°}$

$\huge\boxed{C=40°}$

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Answer 2

angle A = angle B ( Opposite angles of equal sides)

So, angle A = 70°

In Triangle ABC,

angle A+ angle B+ angle C = 180° (Angle sum property)

or 70°+70°+ angle C = 180°

or 140°+ angle C = 180°

or angle C = 180°-140°

or angle C = 40°

Therefore, angle A = 70° and angle C= 40°