Question

in the figure BC = AC , CD =CE . if angle abc equal to 50 degree then find angle ced​

Answer 1

Answer:

Given, BC =AC

and CD =CE

Therfore Angle ABC = Angle BAC=50

Angle ACB = 80 ( 180-50+50 )

We know that by theorem

Angle CED+Angle CDE=Angle ACB

Let Angle CDE and Angle CED be x

Then, X+X=80

2X=80

X=40

Hence Angle CEB =40