Question

in the figure BD bisects angle ABC.prove that AB/BD=BE/BC​

Answer 1

Given :-

• BD bisect ∠ABC .

To Prove :-

• AB / BD = BE / BC.

Construction :-

• Join DC.

Solution :-

In ∆ABE and ∆DBC , we have ,

→ ∠ABE = ∠DBC . { ∵ BD is angle bisector of ∠ABC .}

→ ∠BAE = ∠BDC. { All angles inscribed in a circle and subtended by the same chord are equal. }

So,

→ ∆ABE ≅ ∆DBC . { By AA Similarity. }

Therefore,

→ AB/BE = DB/BC .

Or,

→ AB / DB = BE / BC . { cross - Multiply. }

Hence,

→ AB/BD = BE/BC . (Proved.)

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Answer 2

Answer:

Proved

Step-by-step explanation:

AB/BD=BE/BC Hence proved in above picture

Hope it helps