Question

In the figure below, a nonconducting rod of length L = 7.00 cm has charge -q = -4.04 fC uniformly distributed along its length.

(a) What is the linear charge density of the rod? (in C/m)

(b) What is the magnitude of the electric field at point P, a distance a = 12.0 cm from the end of the rod? (in N/C)

(c) What is its direction? (counterclockwise from the positive x axis)

(d) What is the electric field magnitude produced at distance a = 50 m by the rod?(in N/C)

(e) Repeat part (d) for a particle of charge -q = -4.04 fC that replaces the rod.(in N/C)

Answer 1

Explanation:

Linear charge density = charge/length

=q/L

E=integral kdq/r^2 =kdq/(x)^2

q/L=dq/dx

dq=q/L(dx)

E=integral kqdx/L(x)^2

E=kq/L(integral dx/(x)^2

E=-2kq/L{1/x}

E=2kq/a+L