in the. figure below ABCD and ABEF are parellograms prove CDFE is a parellogram
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The parallelograms ABCD nd ABEF are on the same base BA nd b/w the same parallels CD nd EF..so ar.(parallelogramABCD)= ar.(parallelogramABEF )
Therefore corresponding sides must also be equal nd parallel i.e., CD=EF nd CD parallel to EF..so CDEF is a parallelogram..
Therefore corresponding sides must also be equal nd parallel i.e., CD=EF nd CD parallel to EF..so CDEF is a parallelogram..
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from figure
AB||EF. (ABEF is a ||gm)
AB||DC. (ABCD is a ||gm)
so, EF||DC ------1
also
AB =EF &AB = DC ( same reason as above )
so, EF=DC -------2
from 1 &2
CDFE is a ||gm
AB||EF. (ABEF is a ||gm)
AB||DC. (ABCD is a ||gm)
so, EF||DC ------1
also
AB =EF &AB = DC ( same reason as above )
so, EF=DC -------2
from 1 &2
CDFE is a ||gm
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