Question

In the figure below ABCD is a rectangle in which AB = 12 cm, BC = 8 cm; E is a point
on BC such that BE = 5 cm. AE, when produced meets DC produced at F.
(0) Calculate the length of AE.
() Prove that triangles ABE and FCE are similar; hence evaluate the length of EF.
- 12 cm
[ICSE 1987)​

Answer 1

in triangle ABE BY PYTHAGORAS THEORM. AE = 13 cm

in ∆abe and ∆fec

angle BEA = angle FEC...( OPPOSITE ANGLES)

angle EBA= angle ECF(EACH 90°)

angle EAB= angle EFC

HENCE ∆ ABE AND ∆ FEC ARE SIMILAR

Answer 2

Step-by-step explanation:

i have attached the answer in picture format, thank me later