Question

in the figure below, ABCD is a square and P is the midpoint of AD. BP and CP are joined. prove that angle PCB is equal to angle pbc

Answer 1

This is the answer of your question.

Answer 2

quadrilateral ABCD is a square
so,
AB=CD........ sides of square.......(1)

P is midpoint of side AD
so,
AP=PD………..………………………………(2)

in ∆ABP and ∆DCP
AB=CD ………………………………………from 1
<A=<D........………………………………….both 90°
AP=PD………………………………………..from 2
so ∆ABP congruent to ∆DCP
PC=PB………………………………………..(3)
In ∆PCB
PC=PB……………………………………….. from 3
so,
<PCB=<PBC



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