Question

In the figure below, AP is parallel to CD. Angle PAB is equal to 135⁰ and angle DCB is equal to 147⁰. Find the angle ABC​

Answer 1

Step-by-step explanation:

Given

PQ∥RS

∠PAB=70

0

∠ACS=110

0

∠BAC=?

∠BCS=180−110=70

0

(straight line)

∠DAB=∠ABC=70

0

(alternate angle)

Now from △ABC

By angle sum property

∠BAC+70+70=180

0

∠BAC=40

0