Question

In the figure below, AP is parallel to CD. Angle PAB (w) is equal to 155o and angle DCB (z) is equal to 117o. find angle ABC.

Answer 1

Answer:

Step-by-step explanation:

ABC = ABS + CBS

w' and ABS are alternate interior angles So, ABS = w'

z' and CBS are alternate interior angles So, CBS = z'

Angles w and w' are supplementary which gives w' = 180o - w = 180o - 135o = 45o

Angles z and z' are also supplementary which gives z' = 180o - z = 180o - 147o = 33o

Therefore, we have:

ABC = ABS + CBS

ABC = w' + z' = 45o + 33o = 78o

Answer 2

Step-by-step explanation:

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