In the figure below, not drawn to scale, CDEF is a trapezium, where CF // DE and ∠CFE = 116°. In triangle CDE, CD = DE and ∠DCE = 58°. Find ∠CEF.
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Answer:
Alright
Step-by-step explanation:
Angle dec=angle dce.(it is isosceles triangle)
Angle dec=58
Angle fce=58(alternate interior angle)
Therefore,
In triangle cfe
116+58 +cef=180
174 +cef=180
Cef=6
That is your answer
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