In the figure below, seg. PQ ∥ BC. If AP = 15, PB = 12, AQ = 14, find CQ. *
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side AB || side PQ || side DC [Given] ∴ AP/PD = BQ/QC [Property of three parallel lines and their transversals] ∴ 15/12 = BQ/14 ∴ BQ = (15 x 14)/12 ∴ BQ = 17.5
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