Question

In the figure below the lines AB and CD are parallel and M is the mid point of AB.
1) Compute the angles of AAMD, AMBC and ADCM?
i) What is special about the quadrilaterals AMCD and
MBCD?
​

Answer 1

Answer:

in which class are you?

if you are below 9th standard then I can help you dear

Answer 2

given , DC parallel to AB , ADAB = 40 , AABC , = 60, M is the midpoint of AB

AM = MB = 6 cm . , DC =6 cm

i) quadrilaterals AMCD and

MBCD are parrallelogram because , DC = AM and DC = MB and

DC parallel to AB  

1) ADAM = ADCM  = 40 and ACBM = AMDC = 60 (opposite angle of parallelogram is equal )

therefore ,

ADCM  = 40

ACBM = 60

AMDC = 60 and the diagnol of prallelogram bisect each other so ,

AADC = 60 + 60 = 120

AAMC = 120    (opposite angle of parallelogram is equal)