In the figure, BEST is a rhombus, then the value of y – x is (a) 40° (b) 50° (c) 20° (d) 10°
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BEST is a rhombus,So, TS || BS∠SBE = ∠BST = 40° (alternate interior angles)As Diagonals of a rhombus bisect at right angles.∠y = 90°
In Δ TSO,
∠STO + ∠OST = ∠EOS (Exterior angle property)
⇒ x + 40° = 90° ⇒ x = 90° - 40° ⇒ x = 50°
So, y - x = 90° - 50°
= 40°
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