In the figure BL, AM and CN are parallel to each other and AP, BQ are also parallel to each other, then
x°-y°+ 22° is
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NDP and ADC are vertically opposite angles. If, NDP = 3z, then ADC is also = 3z.
ADC and DCB are co- interior angles. So, their sum is = 180 degrees.
ADC+DCB = 180 degrees
3z+105 degrees = 180 degrees
3z = (180-105) degrees
z = 75/3 degrees
z = 25 degrees.
AM and CN are parallel to each other. So, MAP = NDP
3z = 2y
3*25(value of z = 25) = 2y
75/2 = y
y = 37.5 degrees.
LDC and NCB are co- interior angles. So, their sum is = 180 degrees
x+105 = 180 degrees
x = 75 degrees.
Now, x degree+y degree+22 degree = 75+37.5+22 = 134.5 degrees
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