Question

In the figure BO and CO are bisectors of Angle B and angle C respectively. find the value of angle BOC where angle A is 50°.
Please tell me fast ​

Answer 1

Answer:

As BO and CO are the angle bisectors of external angles of△ABC, Then

∠1=∠2

∠4=∠3

We know, ∠A+∠ABC+∠ACB=180 ∘. …eqn(1)

And ∠ABC=180−2∠1

∠ACB=180−2∠4

Putting it in the eqn (1), we get

∠A+180−2∠1+180−2∠4=180

⇒∠1+∠4=90+ 1/2 ×∠A. …eqn(2)

Also we know from the figure, ∠BOC+∠1+∠4=180 ∘

∠BOC=180−∠1−∠4

From eqn (2)

∠BOC=180−90− 1/2× ∠A

⇒∠BOC=90 ∘ − 1/2× ∠A

=90 - 1/2 × 50

ANS =65°

Answer 2

Answer:

sorry the given question is confusing