Question

in the figure BP bisects angle abc pm is perpendicular to AB and PN is perpendicular to BC under what condition will the triangle PBN ? show that P is equi distant from BA and BC

Answer 1

Answer:

PQ= PR

Step-by-step explanation:

in triangle BPQ and triangle BPR

Angle BQP = Angle BRP = 90°

Angle QBP= Angle RBP ( BCOZ pb is the bisector of angle ABC)

PB = PB (COMMON)

HENCE both the triangles are congruent to each other.

so, PQ= PR (by cpct)