In the figure, BP: PQ: QC = 1:2:1. Area of triangle APQ is 8 sq.cm.
i) Find the area of triangle ABP
ii) Find the area of triangle ABC
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Answer:
a. BP : PQ = 1:2
Area of ∆ ABP is half the area of ∆ APQ.
Area of ∆ ABP = 12 x 8 = 4 sq.cm
b. Area of ∆ ABC = 4 + 8 + 4 = 16 sq.cm
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