Question

in the figure CD perpendicular AB angle ABE =130 and angle BAC =70 find x and y

Answer 1

this is your ans ohk

Answer 2

angle ABE = 130° , angle BAC = 70°

sum of linear angles = 180°

angle ABE + angle ABC = 180°

130° + angle ABC = 180°

angle ABC = 50°

and angle ACB = x + y

in triangle ABC ,

sum of all the angles of triangle = 180°

angle ABC + angle ACB + angle BAC
= 180°

50° + ( x + y) + 70° = 180°

x + y = 60° ---------(1)

here CD is the perpendicular bisector drawn from vertex C to the opposite side AB
thus , angleADC = 90°

in triangleADC ,

angle ADC + y + angleDAC = 180°

90° + y + 70° = 180°

y = 20°

since from(1) , x + y = 60°

then x = 60° - y = 60° - 20° = 40°

Answer: x = 40° , y = 20°