in the figure certain measures of angles are given with the help of this information show that ray BA||ray EF
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i really hope that it helps you
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∠ABC=130°
Step-by-step explanation:
Let draw a line Parallel to BA & DE passing through C
Line is PQ passing through C
PQ∣∣BA∣∣DE
∠DCP=∠CDE
=>∠DCP=100°
∠DCP+∠DCQ=180°
100°+∠DCQ=180°
∠DCQ=80°
∠PCB=∠DCQ+∠DCB
=>∠PCB=80°+50°
=>∠PCB=130°
∠ABC=∠PCB
=>∠ABC=130°
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