Question

In the figure chord ab of circle with Centre O is produced to C such that BC is equal to ob SEO is joined and produced to meet the circle in D if angle ACD is equal to Y and Angle A ODI is equal to X show that x is equal to 3 y

Answer 1

Answer:

where is the figure

Step-by-step explanation:

Answer 2

Solution:-

It is given that AB is a chord of a circle with centre O ans AB is produced to C such that BC=OB

We know that ∠BOC and ∠BCO form isosceles triangle

∠BOC=∠BCO=y⁰

We know that OA and OB are the radii of same circle

OA=OB

We know that ∠OAB and ∠OBA form isosceles triangle

∠OAB=∠OBA=2y⁰

From the figure we know that

Exterior ∠AOD=∠OAC+∠ACO

It can be written as

Exterior ∠AOD=∠OAB+∠BCO

So we get

Exterior ∠AOD=3y⁰

It is given that

∠AOD=x⁰

So we get

x⁰=3y⁰

Therefore it is proved that x=3y