in the figure, CP and CQ are tangent to a circle with centre O. ARB is another tangent touching at the circle at R.if QC=11cm and BC=7cm
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CQ and CP are the tangents to a circle
So, CQ=CP (Tangents to a circle from a common point (C) are equal in length)
CP=CQ=11
Also, BC+BQ=11
⇒BC+7=11
⇒BQ=4
So, BR=BQ=4. (Tangents to a circle from a common point (B) are equal in length)
Thus, option D will be the answer.
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