Question

In the figure,DE ||BC

If DB=6cm,AE=2cm,EC=4cm
Find the length of AD

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Answer 1

HERE DB=6CM

AE=2CM

EC=4CM

ACCORDING TO THALES THEOREM WE KNOW THAT

AD/DB=AE/EC

AD/6 = 2/4

AD/6 =1/2

2AD=6

THEREFORE,

AD=6÷2

SO, AD=3cm

HENCE YOUR ANSWER IS___ 3cm

HOPE THIS HELP YOU ❤️

Answer 2

Given : DE//BC

DB = 6cm, AE = 2cm, EC = 4cm

Find : AD = ?

⬇ Solution ⬇

THEOREM : If one side of triangle 1 is parallel to a side of triangle 2, then the triangles are similar.

So, ∆ADE ~ ∆ABC

Here,

AB = AD+DB = AD+6

AC = AE+EC = 6

then, AD/AB = AE/AC = DE/BC

now taking⬇

AD/AB = AE/AC

AD/AD+6 = 2/6

AD/AD+6 = 1/3

3AD = AD+6. (Cross multiplication)

2AD = 6

AD = 3

Thus, the value of 'AD' is '3'.

❤❤Hope it helps you dear.❤❤