Question

In the figure DE//BC. SL AD=1.7cm, AB-68
and AC=9cm. Find AE.
2
6
Solutions
C​

Answer 1

Answer:

Step-by-step explanation:

Dhwanibudhiraja2004Ambitious

In triangle ABC,

DB= AB-AD

= 6.8 - 1.7

=5.1 cm

Since, DE is parallel to BC,

AD/DB = AE/EC

= AD/DB = AE/AC-AE

= 1.7/5.1 = AE/9-AE

= 1.7 (9 - AE) = 1.5 AE

= 15.3 - 1.7AE = 1.5 AE

= 15.3 = 1.5AE + 1.7AE

=15.3 = 3.2AE

AE = 15.3/ 3.2

AE= 4.7 cm

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Answer 2

Answer:

Step-by-step explanation:

if AD=6.8 then,

In triangle ABC,

DB= AB-AD

= 6.8 - 1.7

=5.1 cm

Since, DE is parallel to BC,

AD/DB = AE/EC

= AD/DB = AE/AC-AE

= 1.7/5.1 = AE/9-AE

= 1.7 (9 - AE) = 1.5 AE

= 15.3 - 1.7AE = 1.5 AE

= 15.3 = 1.5AE + 1.7AE

=15.3 = 3.2AE

AE = 15.3/ 3.2

AE= 4.7 cm

or if ab=68 then,

Since DE || BC,

∴ AB/AD=AC/AE

∴ 68/17=9/AE

or , AE = 9/4= 2.25cm

Hope it helped! :-)