Question

In the figure, DE=DF and PD is the bisector of angle EDF

(i) State three-pairs of equal parts in triangles DPE and DPF.
(ii) Is DPE = DPF? Give reasons.
(iii) Is E = F? Give reasons.​

Answer 1

Answer:

Given A △ABC in which D is the mid-point of side BC and ED is the bisector of ∠ ADb, meeting AB in E, EF is drawn parallel to BC meeting ...