Question

IN THE FIGURE DE PARALLEL AC AP AND CP BISECT BASE ANGLES . PROVE THAT
DE=AD+CE

Answer 1

Answer:

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Given ,

The area of a parallelogram is 216 cm²

The base of parallelogram is 6 times the height

Let ,

The height of parallelogram be " x "

We know that , the area of parallelogram is given by.

$\boxed {\sf{Area = base \times height}} </p><p>Area=base×height$

Thus ,

$\begin{gathered} \sf \mapsto 216 = x \times 6x \\ \\ \sf \mapsto {(x)}^{2} = 36 \\ \\ \sf \mapsto x =± 6 \: m\end{gathered}$

Since , the length can't be negative,

$\therefore \underline{ \sf{ The \: height \: of \: parallelogram \: is \: 6 \: m}}∴ </p><p>Theheightofparallelogramis6m$

I hope it is helpful for you

@ Aman jha[/tex]