In the figure DH perpendicular on
Side Ef Cand seg gk perpendicular on
Side EF If GK = 200m
and A(∆DEF) = 300cm²
find 1. EF
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Answer:
seg DH ⊥ side EF
seg GK ⊥ side EF
DH = 12 cm
GK = 20 cm
A (Δ DEF) = 300 cm ²
To find:
(i) EF
(ii) A (ΔGEF)
(iii) A (⎕ DEGF)
Solution:
(i) Finding EF:
In Δ DEF, we have
EF = base
DH = height = 12 cm
Area (Δ DEF) = 300 cm²
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