Question

In the figure each side of the triangle ABC is extended.angle ABC=80°, angle ACD=120°
a) what is the measure of angle BAC?
b) what is the measure of angle BAE?
c) angle BAE+angle FBC+angle ACD=

Answer 1

Answer:

Given: AB=AC, ∠ACD=130

∠ACD+∠ACB=180 (Linear pair)

130+∠ACB=180

∠ACB=50

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Now, In △ABC,

∠ABC=∠ACB=50 (Isosceles triangle property)

Sum of angles = 180

∠ABC+∠ACB+∠BAC=180

50+50+∠BAC=180

∠BAC=80

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