Question

in the figure EF ll AC if BC =10 CM, AB=13CM AND EC = 2 CM FIND AF
the figure is a triangle ABC.
F intersects AB and joins a point E on BC

Answer 1

if this is helpful to you then please mark as brainlist answer

Answer 2

AF = 2.6 cm

Step-by-step explanation:

Given:

Here, BC = 10 cm, AB = 13cm AND EC = 2 cm

Also EF║AC

so by Basic Proportionality Theorem,

$\frac{BF}{AF} = \frac{BE}{EC}$

⇒ $\frac{AB-AF}{AF} = \frac{BC-EC}{EC}$

⇒ $\frac{13-AF}{AF} = \frac{10-2}{2}$

⇒ $\frac{13-AF}{AF} = \frac{8}{2}$

⇒ $\frac{13-AF}{AF} = 4$

⇒ 13−AF = 4 AF

⇒ 13 = 4 AF + AF

⇒ 13 = 5 AF

⇒ $AF = \frac{13}{5}$

⇒ AF = 2.6 cm