in the figure figure AOB is a straight line find the value of x find ANGLE AOC=(3x-5°) and angle COD=55° and angle DOB=x+20°
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Answered by
37
AOB is straight line
x = ?
angle AOC + angle COD + angle DOB = 180
(3x-5) + 55 + x + 20 = 180
3x+x+55+20-5 = 180
4x+75-5 = 180
4x+70 = 180
4x = 180- 70
4x = 110
x = 110/4
x = 27.5
hope it helps.
x = ?
angle AOC + angle COD + angle DOB = 180
(3x-5) + 55 + x + 20 = 180
3x+x+55+20-5 = 180
4x+75-5 = 180
4x+70 = 180
4x = 180- 70
4x = 110
x = 110/4
x = 27.5
hope it helps.
Answered by
16
Answer:
AOB is straight line
x = ?
angle AOC + angle COD + angle DOB = 180
(3x-5) + 55 + x + 20 = 180
3x+x+55+20-5 = 180
4x+75-5 = 180
4x+70 = 180
4x = 180- 70
4x = 110
x = 110/4
x = 27.5
hope it helps.
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