: In the figure, find PS, if PQ = QR = 1 cm and
RS=√2cm
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Given:- PQ = QR = 1 cm and RS = √2 cm
PQR and PRS are right angled triangle.
Let's Start:- In ΔPQR Right angled at Q
so, PR² = PQ² + QR² [ By Pythagoras Theorem ]
⇒ PR² = 1² + 1²
⇒ PR = √2
now, In ΔPRS Right angled at R
so, PS² = RS² + PR² [ By Pythagoras Theorem ]
⇒ PS² = √2² + √2²
⇒ PS = √4
⇒ PS = 2 cm
∴ PS = 2 cm
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