In the figure find the all four angles A,B,C,D Of the parallelogram
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In triangle BCD,
5x + 3x + 2x =180°
» 10x = 180°
» x = 180/10 = 18°
therefore, angle C = 18 *5 = 90°
And angle A =90° [opposite angles are equal]
Now, angle B = 180-90 = 90° [adjacent angles are supplementary]
And angle D = 90°
Hope it helps...
5x + 3x + 2x =180°
» 10x = 180°
» x = 180/10 = 18°
therefore, angle C = 18 *5 = 90°
And angle A =90° [opposite angles are equal]
Now, angle B = 180-90 = 90° [adjacent angles are supplementary]
And angle D = 90°
Hope it helps...
sbbbbhhJ6494:
Suar ki aulaad adjacent angles are supplementary nhi aata co-interior angles are supplementary aayega
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