Question

In the figure, find the four angle A,B,C and D of the Parallelogram ABCD.

Answer 1

In triangle BCD,
5x + 3x + 2x =180°
» 10x = 180°
» x = 180/10 = 18°

therefore, angle C = 18 *5 = 90°
And angle A =90° [opposite angles are equal]

Now, angle B = 180-90 = 90° [adjacent angles are supplementary]

And angle D = 90°

Hope it helps...

Answer 2

in a triangle BCD

angle =5x+3x+2x=180°

10x=180°

x=180°/10=18°

5x=18×5=90°
angle A and C=90°

because opposite angle are equal
Angel B=D =90°
(angles are supplementary)