in the figure , find the four angles . a,b,c,and d in the parallelogram abcd.
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angleBAC+ACB+B=180°
angle sum property of a triangle
4x+5x+6x=180°
x=12°
angleB=6x=6*12=72°
angleD=angleB (opp.angles of a parallelogram)
=72°
angleBAC=angle ACD
ANGLE ACD=4x
angle C = 4x+5x
=4*12+5*12
=48+60
=108° again
angle C= angleD
angle D=108°
HOPE IT WILL HELP YOU
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