Math, asked by freefire8725, 5 months ago

in the figure, find the four angles A , B , C and D of the parallelogram ABCD ( answer = 90 ° each ) class 8th .​

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Answered by bartwalritika1511
2

Answer:

in angle BCD

∆DBC+∆C+∆CDB= 180 °

3x+ 5x+2x= 180°

10x= 180°

x=180/10= 18°

∆C=5x=5*18= 90°

now we know that alternate angles are equal it mns

angle DBC= angle ADB= 3x =3*18=54°

angle BDC= angle ABD= 2x=2*18=36°

now , we know

angle DBC + angle ABD= angle B

3x+2x= 5x= 5*18= 90°

angle B= 90°

same for angle D

angle ADB+ angle CDB= angle D

3x+2x= 5x= 5*18=90°

angle D=90°

now in ∆ABD( sum of triangle is 180°)

angle A+ angle ABD+ angle BDA= 180°

angle A+ 36°+ 54°= 180°

angle A +90°= 180°

angle A= 180 -90 = 90°

Answered by NITESH761
2

Answer:

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