Math, asked by ramirobhai36, 1 year ago

in the figure find the values of X and Y​

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Answered by ganesha108
0

∠CBD is exterior angle of ∆ABC

∠CBD=∠CAB+∠ACB

∠y=50°+30°

∠y=80°

Let point P be at ∠x

In ∆PBD,

∠B+∠D+∠P=180°

∠y+55+∠P=180

80+55+∠P=180

135+∠P=180

∠P=180-135=45°

∠P+∠x=180(linear pair)

45+∠x=180

∠x=180-45=135

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Answered by Sanramkar
0

Answer:

Step-by-step explanation:

Here is your answer.

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