Question

In the figure , find YZ

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Answer 1

in ΔYXO,

by Pythagoras theorem,

YX2 = YO2 + XO2

(13)2 = YO2 + (12)2

169 = YO2 + 144

169 - 144 = YO2

25 = YO2

YO = 5cm

and also,

XO is perpendicular to YZ.

So,

YO = ZO

.: zone = 5cm

.: YZ = 10CM

HENCE PROVE

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