in the figure , from a rectangular region ABCD with AB =20cm, a right triangle AED with AE=12cm and DE =9cm is cut off . on the other end, taking BC as diameter, a semi circle is added . The perimeter of a shaded region is?
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In right △AED, using Pythagoras theorem,
AD 2 =AE 2 +DE 2=9 2+12 2=81+144=225cm
AD= 225=15cm=diameter
Required area = ar. ABCD + ar. semi-circle -
ar △AED=(20×15)+ 1/2× 22/7×( 15/2 ) 2 − 1\2 ×9×12
=300+88.3928−54=334.3928cm 2
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